upper bound of sequence of functions

upper bound of sequence of functions

What function will be an upper bound of the sequence
$f_{n}(x)=\Bigl(1-\frac{x}{n}\Bigr)^{n}\ln(x)$
since $\displaystyle\lim_{n\to\infty}\Bigl(1-\frac{x}{n}\Bigr)^{n}=e^{-x}$
so we should probably bound above by the exponential function.
Someone knows how to do that?

can some tell me that my answer is right or wrong

can some tell me that my answer is right or wrong

If $\mathbb R$^5be a vector space .and
$$W_1={(0,x_2,x_3,x_4,x_5)/x_2,x_3,x_4,x_5\in R}$$and
$$W2={(x_1,0,x_3,x_4,x_5)/x_1,x_3,x_4,x_5\in R}$$be two subspaces of $R^5$
then the dimension of $W1\cap$W_2 is according two me its dimension is 3
as then $W_1\cap W_2$ have elements of the form $$(0,0,x_3,x_4,x_5)$$
hence $W_1\cap W_2$ will be isomorphic to $ R^3$.

LDAP query doesn't return all accounts with specific login

LDAP query doesn't return all accounts with specific login

I have a Windows 2008 domain that I am querying via ldapsearch and if I
use a domain administrator account I get all the users I would expect, but
if I use the service account I created for this purpose I miss random
objects.
For example:
#> ldapsearch -LLL -H ldap://domain-controller.my-domain.com:389 -b
'dc=MY-DOMAIN,dc=COM' -D 'MY-DOMAIN\administrator' -W
'(&(objectClass=Person)(sAMAccountName=*)(memberof=cn=StashTeam,ou=MyTeams,ou=MyDomainUsers,dc=MY-DOMAIN,dc=COM)(!(userAccountControl=514)))'
| grep cn:
I get a list of:
cn: Homer Simpson
cn: Marge Simpson
cn: Bart Simpson
cn: Lisa Simpson
cn: Maggie Simpson
However if I run (using my Service Account):
#> ldapsearch -LLL -H ldap://domain-controller.my-domain.com:389 -b
'dc=MY-DOMAIN,dc=COM' -D 'MY-DOMAIN\ServiceUser' -W
'(&(objectClass=Person)(sAMAccountName=*)(memberof=cn=StashTeam,ou=MyTeams,ou=MyDomainUsers,dc=MY-DOMAIN,dc=COM)(!(userAccountControl=514)))'
| grep cn:
I get a list like:
cn: Homer Simpson
cn: Lisa Simpson
cn: Maggie Simpson

An abelian subgroup of a group of order 32:

An abelian subgroup of a group of order 32:

I know that a group of order 32 has an abelian subgroup of order 16 using
GAP (Groups, Algorithms, Programming). Is there a way without using
programming to show this. Any help will be highly appreciated.

iOS 7 adding UIView to UITableView

iOS 7 adding UIView to UITableView

I am trying to add a UIView to UITableView in iOS 7 to display and "Not
Results" view.
My code works fine in iOS 6, but getting white page in iOS 7.
[self.tableView insertSubview:_nomatchesView
belowSubview:self.tableView];
Anyone run into this issue?
Thanks.

Passing data from C# to unmanaged C++ (using COM Interop)

Passing data from C# to unmanaged C++ (using COM Interop)

I'm using Com Interop method to communicate with unmanaged C++ and C#.
I need to send data to unmanaged C++ from C#.
Im already sending "bool" values values from C# & accessing it through
"VARIANT_BOOL*" in c++.
I need to send a integer from C#. How can i access that integer value in
unmanaged c++ side ?
for example:
C#
public int myValue()
{
return 5;
}
Unmanaged C++
CoInitialize(NULL);
hRes = IMyPointer.CreateInstance(MyNSpace::CLSID_MyClass);
if (hRes == S_OK)
{
//// ??? define x type
IMyPointer->myValue(x);
}

Regex "greedy" check

Regex "greedy" check

I'm trying to use a simple Regex to match a patttern but get some
unexpected results...
The search pattern and results are given below,
public class Test {
public static void main(String[] args) throws IOException {
Pattern p = Pattern.compile(".*xx");
Matcher m = p.matcher("yyxxxyxx");
while (m.find()){
System.out.println("match start");
System.out.println("Start = " + m.start());
System.out.println("End = " + m.end());
System.out.println("Group = " + m.group());
}
}
}
Result:
match start Start = 0 End = 8 Group = yyxxxyxx
Expected Result:
match start Start = 0 End = 4 Group = yyxx match start Start = 4 End = 8
Group = xyxx
Can someone explain how the regex operates ?